Friday 16 August 2013

Hardcopy of Revision notes Series

In order to cater for different types of reader, those who still interested in hardcopy of these series of ebooks,you could buy them from Amazon.com!!!!


p/s: Currently withhold selling in Amazon due to some tax form need to be submitted in order to get the royalties.sorry for the inconvenience cause.


Wednesday 14 August 2013

Clarification of FRCR part 1 BOF

First of all, thanks for buying the FRCR part 1 BOF.
I would like to clarify some of the typo and solution to the questions.

Physics

Q26- is it organ movement?
Answer given explaining the organ movement and IGRT is current trend of treatment.Yup, the answer should be D not E typo mistake.

Q28- do you use E/3 or E/4 to cover 90%? For electron energy selection
Rule of thumb X/5 is the Dmax,X/4 is the 90% isodose & X/3 80% isodose, surface dose is X+70% given in the textbook.
But, in daily practice 90% coverage is calculated by E/3.
Coming back to Q28, tumor depth 4cm and the answer selection given by the FRCR is 8,10,12,15,18MeV...there is no answer given that suit x 4 if using textbook formula of E/4.So, FRCR using E/3 =90% isodose line.
Electron energy selection calculated using the tumor depth not diameter of tumor as isodose is a  join points of equal dose.- a planar representation of the dose distribution, meaning dose will be same at the same line/surface as long as the line/surface cover by the beam.


Q44 - CT simulator limitation. This question should be phrased like
CT simulator limitation except
answer is C.....Dont know what I.I stand for but given in the exam.
wedge is make of leads/steal
bolus is make of wax(tissue equivalent material)

Chemo:

Q24-Which has the least risk of neurotoxicity:
A.  Gemcitabine
B.  Oxaliplatin
C.  Paclitaxel
D.  Docetaxel
E.  Vincristine

Answer: shd be A. typo given B as answer in the book but explanation clearly stated.
Common chemo-induced neurotoxicity agents are platinum(oxali), taxane(doce and pacli) and vinca alkaloids(vincristine)

Radbio:
Q 18
In clonogenic assay, 500 cells plated and irritated, 78 colonies growth .Plating
efficacy of 55%, the surviving fraction is:
A.  15%
B.  20%
C.  28%
D.  35%
E.  80%
Answer: C

SF =   Colony no rad/(Seeded cell no rad x PE)
Solution:
SF= Colony growth after irritated(78)/ [seeded no (500) x 55/100%)
    = 78/(500 x .55)
    = 0.283
Ans given in % then 0.283/1 x 100%
   = 28%